New (MarksStoreArray constructor): Difference between revisions

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==Examples==
==Examples==
<ol><li><var>New</var> is a constructor and as such can be called with no object, with an explicit class name, or with an object variable, even if that object is null:
<ol><li><var>New</var> is a constructor and as such can be called with no object, with an explicit class name, or with an object variable, even if that object is null:
<p class="code"> %ma = new                                   
<p class="code">%ma = new                                   
%ma = %(marksStoreArray of string len 1):new
%ma = %(marksStoreArray of string len 1):new
%ma = %ma:new                               
%ma = %ma:new                               
</p>
</p>
<li>Specifying an image name on the <var>New</var> method is identical to using a simple <var>New</var> with no parameters followed by a <var>[[BindImage (Stringlist subroutine)|BindImage]]</var> method on the new object:
<p class="code">%list = new('IMAGENAME')
</p>
is equivalent to
<p class="code">%list = new
%list:bindImage('IMAGENAME')
</p>
</ol>
</ol>


==See also==
==See also==
{{Template:MarksStoreArray:New footer}}
{{Template:MarksStoreArray:New footer}}

Revision as of 09:49, 18 February 2011

Create new MarksStoreArray instance (MarksStoreArray class)


Syntax

%marksStoreArray = [%(MarksStoreArray Of itemType):]New

Syntax terms

%marksStoreArrayMarksStoreArray object.
(MarksStoreArray) The class name in parentheses denotes a shared method. New can also be invoked via a MarksStoreArray object variable, which may be null.

Usage notes

  • All errors in New result in request cancellation.

Examples

  1. New is a constructor and as such can be called with no object, with an explicit class name, or with an object variable, even if that object is null:

    %ma = new %ma = %(marksStoreArray of string len 1):new %ma = %ma:new

See also